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jAvA 怎么把数组转为list

方法一: ArrayList list = new ArrayList(Arrays.asList(array)); 方法二: public List getList(Object[] obj)throws Exception{ List list = new ArrayList(); for(int i=0;i

1. String[] userid = {"aa","bb","cc"};List userList = new ArrayList();Collections.addAll(userList, userid);2. String[] userid = {"aa","bb","cc"};List userList = Arrays.asList(userid);3. 循环操作数组再add 望采纳。

ArrayList list=new ArrayList(); String strings[]=(String [])list.toArray(); 这样写代码个人觉得应该没什么问题,编译也没有问题。可是具体运行的时候报异常,如下:Exception in thread "main" java.lang.ClassCastException: [Ljava.lang....

java数组转换成为List。 调用Arrays的asList方法. String[] arr = new String[] {"1", "2"}; List list = Arrays.asList(arr);

public static void main(String[] args) { Integer array[]={1,2,3}; ArrayList arrayList=new ArrayList(Arrays.asList(array));}

在开发中有时候我们有时候会将JSONArray转化为list的需求 JSONArray jsonArray = [{"colName":"2017年01月","addNum":"539","totalNum":"8395"},{"colName":"2017年02月","addNum":"447","totalNum":"8888"},{"colName":"2017年03月","addNum":"...

1. String[] userid = {"aa","bb","cc"};List userList = new ArrayList();Collections.addAll(userList, userid);2. String[] userid = {"aa","bb","cc"};List userList = Arrays.asList(userid);3. 循环操作数组再add 望采纳。

import java.util.ArrayList;import java.util.HashMap;import java.util.List;import java.util.Map;public class TestArray { public static void main(String[] args) { /** * 初始化一个 List,存放 String 数组,数组的第一位是 amount,第...

List list = new ArrayList(); Tbconten tb; tb = new Tbconten("01", "jack"); list.add(tb); tb = new Tbconten("02", "tim"); list.add(tb);

String[][] datas = {{"aaa","aa1","aa11"},{"bbb","bb1","bb11"},{"ccc","cc1","cc11"}, {"aaa","aa2","aa22"},{"bbb","bb2","bb22"},{"aaa","aa3","aa33"}, {"bbb","bb3","bb33"}}; Map map = new HashMap(); for (String[] strings : datas) ...

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